How the heck do I calculate my compression ratio?

Veepster · Post by **Veepster** » Wed Aug 06, 2003 1:07 pm

No spacers......Century cylinders...uncut........

peace......BartG

general_lee_jr · Post by **general_lee_jr** » Wed Aug 06, 2003 2:58 pm

This is the easiest way to get the compression. Let me know if you need help!

2^k<2*p<=2^(k+1)2*(2*(p+1)-2^k-1)=2*n-2^(k+1)
e = w + ix

e' = w' + ix'

e' = L(e) = [w.cosh(a) - x.sinh(a)] + i[x.cosh(a) - w.sinh(a)]

a = a0 + ia1

b = b0 + ib1

a.b = (a0.b0 - a1b1) + i(a0b1 - b0a1)

1/a = a/a2 = (a0 + ia1) / (a02 - a12)

e'2 = (L.e)2

= L2.e2

w'2 - x'2 = (cosh2(a) - sinh2(a)).(w2 - x2)

= w2 - x2 = e2

L = 1/(1 - V2/c2)1/2 + i(V/c(1 - V2/c2)1/2)

= c/(c2 - V2)1/2 + i(V/(c2 - V2)1/2)

= (c + iV)/(c2 - V2)1/2

= v/(v2)1/2

a2 = (w2 - x2)

a2n = (w2 - x2)n
= w + ix

a(2n + 1) = (w2 - x2)n . a or

a(2n + 1) = a.(w2 - x2)n

(a + b)2 = a2 + a.b + b.a + b2

(a + b)2 = a2 + a.b + (a.b)* + b2

= a2 + 2Re(a.b) + b2

p(x) = a0 + a1.x + a2.x2/2! + a3.x3 /3! ...

= f(s) + x.g(s)

a = a0 + a1i + a2j + a3k

b = b0 + b1i + b2j + b3k

a.b = (a0b0 + a1b1 + a2b2 + a3b3) +

(a0b1 + a1b0 + a2b3 - a3b2)i +

(a0b2 + a2b0 + a3b1 - a1b3)j +

(a0b3 + a3b0 + a1b2 - a2b1)k

a = a0 + v ; where v = a1i + a2j + a3k

b = b0 + u ; where u = b1i + b2j + b3k

a.b = (a0b0 + a1b1 + a2b2 + a3b3) +

(a0b1 - a1b0 + a2b3 - a3b2)i +

(a0b2 - a2b0 + a3b1 - a1b3)j +

(a0b3 - a3b0 + a1b2 - a2b1)k

a = a0 + v ; where v = a1i + a2j + a3k

b = b0 + u ; where u = b1i + b2j + b3k

Then a.b = a0b0 + v.u + a0u - b0v + v X u]

a2 = (a02 - a12 - a22 - a32)
f(s) = [p(x)]2 ; s = x2

general_lee_jr · Post by **general_lee_jr** » Wed Aug 06, 2003 2:59 pm

This is the easiest way to get the compression. Let me know if you need help!

2^k<2*p<=2^(k+1)2*(2*(p+1)-2^k-1)=2*n-2^(k+1)
e = w + ix

e' = w' + ix'

e' = L(e) = [w.cosh(a) - x.sinh(a)] + i[x.cosh(a) - w.sinh(a)]

a = a0 + ia1

b = b0 + ib1

a.b = (a0.b0 - a1b1) + i(a0b1 - b0a1)

1/a = a/a2 = (a0 + ia1) / (a02 - a12)

e'2 = (L.e)2

= L2.e2

w'2 - x'2 = (cosh2(a) - sinh2(a)).(w2 - x2)

= w2 - x2 = e2

L = 1/(1 - V2/c2)1/2 + i(V/c(1 - V2/c2)1/2)

= c/(c2 - V2)1/2 + i(V/(c2 - V2)1/2)

= (c + iV)/(c2 - V2)1/2

= v/(v2)1/2

a2 = (w2 - x2)

a2n = (w2 - x2)n
= w + ix

a(2n + 1) = (w2 - x2)n . a or

a(2n + 1) = a.(w2 - x2)n

(a + b)2 = a2 + a.b + b.a + b2

(a + b)2 = a2 + a.b + (a.b)* + b2

= a2 + 2Re(a.b) + b2

p(x) = a0 + a1.x + a2.x2/2! + a3.x3 /3! ...

= f(s) + x.g(s)

a = a0 + a1i + a2j + a3k

b = b0 + b1i + b2j + b3k

a.b = (a0b0 + a1b1 + a2b2 + a3b3) +

(a0b1 + a1b0 + a2b3 - a3b2)i +

(a0b2 + a2b0 + a3b1 - a1b3)j +

(a0b3 + a3b0 + a1b2 - a2b1)k

a = a0 + v ; where v = a1i + a2j + a3k

b = b0 + u ; where u = b1i + b2j + b3k

a.b = (a0b0 + a1b1 + a2b2 + a3b3) +

(a0b1 - a1b0 + a2b3 - a3b2)i +

(a0b2 - a2b0 + a3b1 - a1b3)j +

(a0b3 - a3b0 + a1b2 - a2b1)k

a = a0 + v ; where v = a1i + a2j + a3k

b = b0 + u ; where u = b1i + b2j + b3k

Then a.b = a0b0 + v.u + a0u - b0v + v X u]

a2 = (a02 - a12 - a22 - a32)
f(s) = [p(x)]2 ; s = x2

Guest · Post by **Guest** » Wed Aug 06, 2003 3:07 pm

I know that is why I posted!!!..

Imagine me sitting in my garage after a couple of suds beating on my calculator...it was an ugly sight!!

Peace....BartG

general_lee_jr · Post by **general_lee_jr** » Wed Aug 06, 2003 3:57 pm

After a few beers the math pretty much does itself.

Veepster · Post by **Veepster** » Wed Aug 06, 2003 5:54 pm

I had no problem with the math!......I was just wondering how I was going to suppress detonation with 36.9:1 compression!!

Peace..............BartG

bedlamite · Post by **bedlamite** » Wed Aug 06, 2003 6:58 pm

No problem, just use 1437 octane

general_lee_jr · Post by **general_lee_jr** » Thu Aug 07, 2003 5:55 am

36.9:1 is great for a daily driver. Hell a diesal runs about 25:1. Thats it! We will use diesal fuel for now on and install some glow plugs.